By pulling slowly, we can say that a is approximately zero, so
TT - TB - W = 0.
TT - TB = W
So TT is always larger than TB and the top thread
will break first.
Now, consider what happens when the lower thread is pulled
sharply.
We are trying to give the stone a large acceleration downward:
TB - TT= - W + ma = -mg + ma
If the attempted acceleration is greater than ag, then TB
will be greater than TT and the bottom string will break
first.